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Can one get fitted value without going to predict?

2 ビュー (過去 30 日間)
alpedhuez 2021 年 7 月 29 日
コメント済み: alpedhuez 2021 年 7 月 30 日
I have a regression
How can one obtain the fitted value of the regression without going for predict?
  1 件のコメント
Scott MacKenzie
Scott MacKenzie 2021 年 7 月 30 日
I had posted an answer but then read Jeff's answer, posted a few hours after mine. As Jeff is "guessing" so was I.
@alpedhuez, if Jeff's answer is what you are looking for, that's great. Please accept his answer.
If it's not what you are looking for, then please explain what you want. Explain what you mean by "fitted value" (why singular? coefficients? predictions? just one prediction? closeness of fit? etc.) and "without going for predict".



Jeff Miller
Jeff Miller 2021 年 7 月 30 日
From your reference to 'predict', I'm guessing you have a vector of observed x values and you want to compute the predicted y for those x's. If so, then you want something like this:
xwithintercept = [1 x]; % maybe x' depending on row vs column vector
predictedY = sum( xwithintercept .* mdl.Coeffificent.Estimate)
  1 件のコメント
alpedhuez 2021 年 7 月 30 日
I had hoped that
had saved the value so that one can just reference it.


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