How can I change the width of a tile in a tiledlayout without changing its height?

265 ビュー (過去 30 日間)
Wiqas Ahmad
Wiqas Ahmad 2021 年 7 月 28 日
回答済み: Chunru 2021 年 7 月 28 日
I'd like to decrease the width of each tile so that it looks like a vertical rectangle instead of square with vertical axis longer than horizantal. I have the following code for the figure
figure(1)
t = tiledlayout(1,3,'TileSpacing','Compact','Padding','Compact');
%Tile 1
nexttile
hold on
plot(theta,numer(1,:),'color',col(1),'LineWidth',2);
plot(theta,numer(2,:),'color',col(2),'LineWidth',2);
plot(theta,numer(3,:),'color',col(3),'LineWidth',2);
plot(theta,numer(4,:),'color',col(4),'LineWidth',2);
xlabel('\fontname{Arial}Scattering angle \theta(\circ)','FontSize',14,'FontWeight','normal');
ylabel('\fontname{Arial}Phase function P_{L\perp}(\theta)(sr^-^1)','FontSize',14,'FontWeight','normal');
set(gca,'color','w','Fontsize',12,'LineWidth',1,'Fontweight','normal');
set(gca,'box','off','Fontname','Arial','Fontsmoothing','on');
set(gca,'xgrid','on','ygrid','on','gridcolor','k');
legend('R_{eff}= 4\mum','R_{eff}= 8\mum','R_{eff}= 13\mum','R_{eff}= 18\mum','location','Northeast');% we need to calculate Reff from Rm using formaula
legend boxoff
set(gca,'yscale','log');
%yMin = floor(min(numer(i,:)));
%yMax = ceil(max(numer(i,:)));
set(gca,'xlim',[0 60],'xtick',[0:20:60],'ylim',[1e-5 1e-2],'ytick',10.^(-5:1:-2));
set(gca,'color','w','Fontsize',12,'LineWidth',1,'Fontweight','normal');
set(gca,'box','off','Fontname','Arial','Fontsmoothing','on');
set(gca,'xgrid','on','ygrid','on','gridcolor','k');
text(10,10.^(-2.22),'S_{0}=(1,-1,0,0)','Color','black','FontSize',14,'FontWeight','normal','FontName',...
'Arial')
nIDs = 1;
alphabet = ('a':'z').';
chars = num2cell(alphabet(1:nIDs));
chars = chars.';
charlbl = strcat('(',chars,')'); % {'(a)','(b)','(c)','(d)'}
text(0.05,0.95,charlbl{1},'Units','normalized','FontSize',14)

採用された回答

Chunru
Chunru 2021 年 7 月 28 日
By changing figure size, you can achive that effect.
figure('Position', [1, 1, 600, 400])
t = tiledlayout(1,3,'TileSpacing','Compact','Padding','Compact');
nexttile; plot(randn(5));
nexttile; plot(randn(5));
nexttile; plot(randn(5));
figure('Position', [1, 1, 600, 200])
t = tiledlayout(1,3,'TileSpacing','Compact','Padding','Compact');
nexttile; plot(randn(5));
nexttile; plot(randn(5));
nexttile; plot(randn(5));

その他の回答 (1 件)

Dave B
Dave B 2021 年 7 月 28 日
I can think of a couple of easy options, depending on where the space should go:
Option 1, use pbaspect on the axes. This will distribute the axes (which means there's a lot of space in between them)
tiledlayout(1,3,'TileSpacing','Compact','Padding','Compact')
nexttile
plot(rand(100,1))
pbaspect([1 5 1])
nexttile
plot(rand(10,1))
pbaspect([1 5 1])
nexttile
bar(1:10)
pbaspect([1 5 1])
exportgraphics(t,'opt1.png') % picture below
Option 2: adjust the layout Position (this will keep the axes together, putting the space at one side):
t = tiledlayout(1,3,'TileSpacing','Compact','Padding','Compact')
nexttile
plot(rand(100,1))
nexttile
plot(rand(10,1))
nexttile
bar(1:10)
t.Position(3)=.4;
exportgraphics(t,'opt2.png') % picture below

カテゴリ

Help Center および File ExchangeAxis Labels についてさらに検索

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by