Same Function but Different Result (Basic Function)

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CVR
CVR 2013 年 9 月 30 日
コメント済み: CVR 2013 年 10 月 1 日
Hi all, can anybody help me ? I have 2 same functions here, but when I evaluate them, I got a slightly different result. Perhaps someone could help me to check it ? Thank you
The first version is
t = [4:1:14];
A0 = 23
rho = 1.2
Ton = 1.2
Toff = 6
r = 0.6
del_a = 3.8
del_m = 0.1
p = t>=Ton;
q = t <Toff;
s = t>=Toff;
A = (A0*exp(rho.*(t - Ton)).*p.*q) + (A0*exp(rho*(Toff - Ton))*exp(-(r+del_a).*(t - Toff))).*s;
M = ((r/(r+del_a - del_m))*(A0*exp(rho*(Toff - Ton))*exp(-del_m.*(t-Toff)) - A)).*s;
y = A+M
plot(t,y)
and the second version is :
t = [4:1:14];
Par(1) = 23
Par(2) = 1.2
Par(3) = 1.2
Par(4) = 6
Par(5) = 0.6
Par(6) = 3.8
Par(7) = 0.1
model = @(Par,t) ( ( Par(1)*exp(Par(2).*(t - Par(3))).*(t>=Par(3)).*(t < Par(4)) )...
+ ( Par(1)*exp(Par(4) - Par(3))*exp(-(Par(5)+Par(6)).*(t - Par(4))).*(t >= Par(:,4)))...
+ ( (Par(5)/(Par(5) + Par(6) - Par(7))) *( (Par(1)*exp(Par(2)*(Par(4) - Par(3))))* ...
exp(-Par(7).*(t - Par(4))) - (( Par(1)*exp(Par(2).*(t - Par(3))).*(t>=Par(3)).*(t < Par(4)) )...
+ ( Par(1)*exp(Par(4) - Par(3))*exp(-(Par(5)+Par(6)).*(t - Par(4))).*(t >= Par(4)))...
) ) ).*(t>=Par(4)) ...
)
y = model(Par,time);
plot(t,y)
the problem is I have a slightly different result, but both of them are a same function. Can anybody help ? What I want to do is to convert my function in the first version into a function handle like in the second version
Thanks very much
  1 件のコメント
Jan
Jan 2013 年 9 月 30 日
編集済み: Jan 2013 年 9 月 30 日
I get the error message "??? Undefined function or variable 'time'." for the second version. Do you mean "t" instead?

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Jan
Jan 2013 年 9 月 30 日
編集済み: Jan 2013 年 9 月 30 日
If I replace "time" by "t", I get this:
y1 = A+M;
y2 = model(Par, t);
y1 - y2
% >> 0, 0, 3875.769e, 47.58413, 0.5842066, 7.172503e-3, 8.805925e-5, 1.081133e-6, 1.327351e-8, 1.629701e-10, 1.989520e-12
This seems to show, that the functions are different.
The 2nd version is very hard to read. I'd really avoid such ugly code, because, as you already see, it is nearly impossible to debug it. Do you have any good reasons to prefer this kind of code?
  3 件のコメント
Jan
Jan 2013 年 10 月 1 日
You can simply write the code into a function and create a function handle either by setting "@" before the name of the function, or by using str2func.
CVR
CVR 2013 年 10 月 1 日
wow, great.. It works Thx

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