Concatenation problem with a loop

How would you concatenate the two different results for D?

>> for X=[1.5 1.7],

D=(X*440)*(1:1:ceil(2000/(X*440)))

end

D =

         660        1320        1980        2640

D =

         748        1496        2244

to look like

D =

          660        1320        1980        2640          748        1496        2244

Answer 1

[Azzi Abdelmalek]

X=[1.5 1.7];
D=[];
for k=1:numel(X)
  D=[D (X(k)*440)*(1:1:ceil(2000/(X(k)*440)))];
end
D

%or

X=[1.5 1.7];
D=cell2mat(arrayfun(@(y) (y*440)*(1:1:ceil(2000/(y*440))),X,'un',0))