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In Simulink how would you change [4x1] signal to [1x1]

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Adam s
Adam s 2021 年 7 月 19 日
コメント済み: Walter Roberson 2021 年 7 月 19 日
I would like to take a signal in simulink for example a =123 and b = 456 and have the output = 123456.
How would you do this?

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Walter Roberson
Walter Roberson 2021 年 7 月 19 日
Arithmetic blocks? One that multiplies by 1000 and the other that adds ?
Or is the range of values not set in advance? Is the range variable? For example if one time a = 123 b = 456 then you want 123456 as output; if the next time a = 123 and b = 45 then would you want 12345 as output, or would you want 123045 as output?
What result do you want if one of the values is negative? If both of them are negative then do you need a negative result?
  3 件のコメント
Walter Roberson
Walter Roberson 2021 年 7 月 19 日
2 (constant block) ->
| max (minmax block) --> [T1]
B ->
[T1] ->
| multiply (product block) -> log10 (math block) -> [T2]
(1+20*eps) (constant block) ->
[T2] -> ceiling (rounding function) -> 10^u (math) ->
| multiply (product block) -> [T3]
A ->
[T3] ->
| add (math) --> result
B ->
In the above, I give an operation name, and then in () I give the name of the block that implements it.
In the above, the [T1] are not operations, but are simply labels to make clearer how the blocks join together
So you take
A * 10^ceil(log10((1+20*eps)*max(B,2))) + B
The max() part is to handle 0 and 1 the same as 2 to 9.
The 1+20*eps part is a hack so that exact powers of 10 such as 1000 get the full number of digits, since ceil(log10(99)) is 2, same as ceil(log10(100)). The constant 20*eps is sufficient up to 1E32... but of course if you are above 1E15 then you have to start worrying about losing precision when you do the concatenation.

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その他の回答 (1 件)

Sameer Pujari
Sameer Pujari 2021 年 7 月 19 日
You can do this
  2 件のコメント
Sameer Pujari
Sameer Pujari 2021 年 7 月 19 日

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