Unable to perform assignment because the left and right sides have a different number of elements.
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Hi all,
I am trying to divide a two line (two times) based on different length as the following code:
but I can not
clear all
clc
t = [2 0.40 1.2];
t_ID = [3 1]; % Each line index
Z = zeros(2+1,1);
for j = 1:2
if (j == 1)
t1 = 0; t2 = t(t_ID(j));
Z(j) = linspace(t1,t2,2);
else
t1 = Z(2*j-1);
t2 = t1+t_av(t_ID(j));
Z(2*j-1:2*j) = linspace(t1,t2,2);
end
end
% Z should be [0 0.2 0.3250]
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回答 (1 件)
Walter Roberson
2021 年 7 月 19 日
First get rid of the "clear all". Your code relies on variables being in memory, but the clear destroys them.
Z(j) = linspace(t1,t2,2);
linspace requesting two output elements is never going to fit a scalar destination. Also linspace requesting two output elements would just be the vector [t1, t2] so just code that instead of confusing things.
When j becomes 2 then 2*j-1 would be 3 so you would be writing to locations 3 and 4 in the vector. Your code will never create a vector of odd length.
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