# How can I code a two variable function?

3 ビュー (過去 30 日間)
Eduardo Fornazieri 2021 年 7 月 10 日

Hi, could you code this function from ?
I know I can't do it to infinity, so I choose the sum from 0 to 100. Please, help.
.

サインインしてコメントする。

### 採用された回答

ANKUR KUMAR 2021 年 7 月 11 日

You can simply use for loop to iterate x and y. Refer to the below code just for your reference. You might need to make modification as per your need.
This might be the good starting point for you to write code independently.
Anyway, I am getting some of the NaN values.
func = @(n,x,y) (((-1)^n)/((2*n + 1)^3))* sech(((2*n + 1)*pi)/2)*cosh(((2*n + 1)*pi*x)/2)*cos(((2*n + 1)*pi*y)/2);
n_upper_limit=100;
for x=1:5
for y=1:5
u(x,y) = 1- y^2 - ((32)/(pi^3))*(sum(arrayfun(@(n) func(n,x,y), 1:n_upper_limit),'omitnan'));
end
end
disp(u)
1.0e+130 * -0.0000 -0.0000 -0.0000 -0.0000 -0.0000 -0.0000 1.6033 0.0000 -1.6033 -0.0000 NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN NaN
% For plotting u
imagesc(u)
title('Values of u')
xlabel('x values')
ylabel('y values')
xticks([1:5])
yticks([1:5])
colorbar
set(gca,'Ydir','normal')

サインインしてコメントする。

### カテゴリ

Help Center および File ExchangeGeometry and Mesh についてさらに検索

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by