Hi all,
I have a function called details, where the user enters his name, and the details are stored in the array, say "name". Each time a name is entered it should get appended to the array.
At any point, the user can cancel entering the details and do other computations. Then again the user can start entering the details. In this case, it should get appended to the "name" array that is already existing.
At the beginning of the session, the array "name" should be empty.

1 件のコメント

Azzi Abdelmalek
Azzi Abdelmalek 2013 年 9 月 18 日
post your code

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 採用された回答

Yatin
Yatin 2013 年 10 月 16 日
編集済み: Yatin 2013 年 10 月 16 日

5 投票

Hi,
A possible solution to your problem could be something like this. Set the array as empty initially(beginning of the session).
nameArray = {};
You can then append the entries in the array as follows:
nameArray = [nameArray, 'Name you want to append'];
This uses the concept of cell array. You might want to refer to the documentation on cell arrays for more information. http://www.mathworks.com/help/matlab/cell-arrays.html

6 件のコメント

Cooper Harris
Cooper Harris 2018 年 10 月 19 日
編集済み: Cooper Harris 2018 年 10 月 19 日
this is an awful answer. does not address how to iteratively update an array ("list" in python). this simply redefines the array and erases past values. the link you posted was helpful though!
James Tursa
James Tursa 2018 年 10 月 19 日
"... this simply redefines the array and erases past values ..."
Really? Did you try it?
Steven Lord
Steven Lord 2018 年 10 月 19 日
If you run both commands over and over again, nameArray will keep only the last name entered.
If you run the first command once to initialize the variable then run only the second line repeatedly to append to the cell array, it will do what the original poster asked.
Bill Tubbs
Bill Tubbs 2020 年 3 月 22 日
Sad that this is the only solution since it's not efficient (reallocates memory each iteration) but what can you do... Thanks!
bla bla
bla bla 2020 年 4 月 13 日
@Bill Tubbs maybe try nameArray(end+1) = {'name to be appended'}; should be a more efficient way of doing it
Xuzhaoqiu Zeng
Xuzhaoqiu Zeng 2021 年 6 月 5 日
testFactor = 194225602
testStart = 3928
tic
mytest = [testStart];
for i = 1:100000
mytest = [mytest, testStart];
end
toc
tic
mytest = [testStart];
for i = 1:100000
mytest(end+1) = testStart;
end
toc
The result is :
2.024820
0.011121
list = [list, appendedNumber] is ridiculous.

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その他の回答 (1 件)

Vinaya Babu Yerneni
Vinaya Babu Yerneni 2020 年 10 月 16 日

0 投票

Firstly you need to clarify whether you need to append strings or integer or string and integer
for only strings
name=input('What is your name? ', 's');
age=input('What is your age? ',"s");
hometown=input('What is your hometown? ', 's');
sport=input('What is your favorite sport? ', 's');
Temptex2=append(name,age,hometown,sport)

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