how to convert a single row matrix into an n bit number
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I am given a numerical array, a = [0 0 1 0 1 0 1]. i have to transform it into n bit number, n = column number,
a = 0010101.
sprintf and other functions ignore the preceding zeros, which isn't helpful.
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Image Analyst
2021 年 7 月 3 日
Try this:
a = [0 0 1 0 1 0 1]
str = sprintf('%d', a)
num = bin2dec(str)
a =
0 0 1 0 1 0 1
str =
'0010101'
num =
21
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