how to calcuate mean with NaN

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Peihong
Peihong 2013 年 9 月 12 日
コメント済み: Esen S. 2020 年 4 月 21 日
Dear Friend,
There are two matrixs with the same size, there are some NaNs in each matrix. I want to calculate the mean of corresponding datapoints, which might contain NaN. for example, A(1,2)=NaN, B(1,2)=3, I need the average of the sum of 3+NaN divided by the effective number of data points, here is 1 since A(1,2) is NaN, to be 3. If A(2,2)=2,B(2,2)=5, I need the average to be (2+5)divided by 2, which equals 3.5 since neither A(2,2) and B(2,2) contains NaN. Is there a way to achieve this goal without using a for loop? thanks

採用された回答

Sven
Sven 2013 年 9 月 12 日
編集済み: Sven 2013 年 9 月 12 日
If you have the Statistics Toolbox, just replace calls to mean() with calls to nanmean().
If you don't have it, you can do the same by downloading the File Exchange contribution nansuite
Here's an example:
A = reshape(1:4,2,2);
B = A + 10;
A([1 3]) = nan % Set some NaNs
B([1 2]) = nan
yourMean = nanmean(cat(3,A,B),3)
Which results in:
A =
NaN NaN
2 4
B =
NaN 13
NaN 14
yourMean =
NaN 13
2 9
  1 件のコメント
Peihong
Peihong 2013 年 9 月 12 日
Hi, Sven, thanks a lot. It's exactly what I need.

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その他の回答 (2 件)

Jan
Jan 2013 年 9 月 12 日
Emulating NANMEAN without the statistics toolbox is easy:
index = isnan(X);
X(index) = 0;
M = sum(X, 2) ./ sum(index, 2);
  1 件のコメント
Esen S.
Esen S. 2020 年 4 月 21 日
I belive there is a tilde missing in the last line.
It should be M = sum(X, 2) ./ sum(~index, 2);

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Shashank Prasanna
Shashank Prasanna 2013 年 9 月 12 日

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