Why is their an offset when I intergrate a simple sin(1*x) in simulink using the (1/s) block?

12 ビュー (過去 30 日間)
Their seems to be a -1 offset when I intergrate a sin(x) signal using a 1/s block. the sin(x) goes from -1 to 1 and the resulting intergation goes from 0 to 2? Is their a paramater i'm missing?

回答 (1 件)

Ryan G
Ryan G 2013 年 9 月 10 日
You need to set the initial condition of the integrator. I believe I cover this a bit in the intro to simulink webinar. This should help you ramp up if you're just getting started.
  2 件のコメント
Ryan G
Ryan G 2013 年 9 月 11 日
You're thinking of the solution analytically instead of numerically. The integral block only receives a value. It doesn't know if the value came from a sin , cos or a constant.
For example: At time t= 0 that value is into the integrator 0, time t=0.1 that value is sin(0.1)=0.0998 and the previous state (t=0) is 0. It will then integrate between those inputs using deltaT=0.1 with an IC of 0.
The time step changes dynamically based on the ODE45 (solver) algorithm tolerances.

サインインしてコメントする。

カテゴリ

Find more on General Applications in Help Center and File Exchange

タグ

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by