Transposing matrix of elements added by for loop
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I am creating a matrix with 38 unique entries. My for loop is creating a 1x38 matrix but I need it to be 38x1 for the operation I'm trying to perform. I tried using transpose but that did not work. How would I transpose this matrix so that I get each element added as a new row instead of a column? This is occuring on the Sol.RHS matrix
for i=1:inds.numinds
for j=1:inds.ind_dat(i).nconn
%
% gather the properties on both sides
%
jind=inds.ind_dat(i).conn_array(j).ind;
jsign=inds.ind_dat(i).conn_array(j).sign;
%
% indices for implicit contribution
%
ivmm=inds.numind*ind_scale_eq + (jind - 1) + 1;
%
% add in implicit and explicit terms - vapor
%
Sol.mat(ivmm,ivmm)=Sol.mat(ivmm,ivmm)+juns.jun_dat(jind).a*jsign/inds.ind_dat(i).volume;
Sol.RHS(ivmm)=transpose(Sol.RHS(ivmm)+juns.jun_dat(jind).a*jsign*inds.ind_dat(jind).vv/inds.ind_dat(i).volume);
end
end
2 件のコメント
Matt J
2021 年 6 月 28 日
I tried using transpose but that did not work
It doesn't seem possible that that would not work.
DGM
2021 年 6 月 28 日
How exactly did it not work? Since there really isn't any information here about the size of any of these variables, I have no idea what would happen. All anyone can go on is your assertion that one of them is 1x38 -- something that any troubleshooting should question if array size/orientation is not meeting expectations. You might want to provide enough data or pseudo-data such that your code constitutes a minimal working example of your problem.
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