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rahman
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hermitian symmetry in IFFT !

rahman
さんによって質問されました 2013 年 9 月 7 日
最新アクティビティ Jakob Ameres さんによって 回答されました 2016 年 5 月 24 日
Hi all. I have a matrix as a 2D spectrum. now, I want to transform it to time domain. when I use IFFT, the results are complex numbers, but it should be real numbers! so I have to have hermitain symmetry. how can i do that?

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Walter Roberson
on 7 Sep 2013
What is the relative scale of the complex portion? Could you simply be encountering round-off problems?
rahman
on 9 Sep 2013
it is about the real part.
Walter Roberson
on 9 Sep 2013
Can you create a small example?
Are you doing anything between the fft and ifft ?

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Honglei Chen
Answer by Honglei Chen
on 9 Sep 2013

If it is some small imaginary part due to numerical precisions, you can probably preprocess your input to IFFT by doing
x = (x+x')/2
This makes x Hermitian

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Answer by Jakob Ameres on 24 May 2016

Use the symmetric flag for the ifft.
ifft( data, [], dim, 'symmetric')

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