hermitian symmetry in IFFT !
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Hi all. I have a matrix as a 2D spectrum. now, I want to transform it to time domain. when I use IFFT, the results are complex numbers, but it should be real numbers! so I have to have hermitain symmetry. how can i do that?
3 件のコメント
Walter Roberson
2013 年 9 月 9 日
Can you create a small example?
Are you doing anything between the fft and ifft ?
回答 (2 件)
Honglei Chen
2013 年 9 月 9 日
If it is some small imaginary part due to numerical precisions, you can probably preprocess your input to IFFT by doing
x = (x+x')/2
This makes x Hermitian
0 件のコメント
Jakob Ameres
2016 年 5 月 24 日
Use the symmetric flag for the ifft.
ifft( data, [], dim, 'symmetric')
0 件のコメント
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