closedloop with delay and difference between Inputdelay and Outputdelay
2 ビュー (過去 30 日間)
古いコメントを表示
Hi all!!
Well, My problem is that I can't find the transfer function of closed loop model with delay.
I use
s=tf('s');
Gp = 250/(s*(1+s/10));
Gp.OutputDelay = 0.05;
feedback(Gp,tf([1],[1]))
and I receive this error
??? Error using ==> lti.feedback at 127 System interconnection gives rise to internal delays and can only be represented in state space. Convert at least one of the models to state space using the "ss" command.
And I don't want to use my model in state space. And i don't wanna use any approximation (pade...), too. Any idea?
I have one more question. Which is the difference between "Gp.InputDelay" and "Gp.OutputDelay" ?
0 件のコメント
採用された回答
Arnaud Miege
2011 年 6 月 2 日
You have no choice but to use state-space:
>> feedback(ss(Gp),tf([1],[1]))
a =
x1 x2
x1 -10 -2500
x2 1 0
b =
u1
x1 64
x2 0
c =
x1 x2
y1 0 39.06
d =
u1
y1 0
(values computed with all internal delays set to zero)
Internal delays: 0.05
Continuous-time model.
Note that in R2011a, it works without converting to state-space:
>> feedback(Gp,tf([1],[1]))
a =
x1 x2
x1 -10 -2500
x2 1 0
b =
u1
x1 64
x2 0
c =
x1 x2
y1 0 39.06
d =
u1
y1 0
(values computed with all internal delays set to zero)
Internal delays (seconds): 0.05
Continuous-time model.
HTH,
Arnaud
2 件のコメント
Arnaud Miege
2011 年 6 月 2 日
InputDelay applies a time delay to the input of the LTI object, whereas OutputDelay applies a time delay to the output of the LTI object, see:
http://www.mathworks.com/help/releases/R2011a/toolbox/control/ug/bstzkhr.html
その他の回答 (0 件)
参考
カテゴリ
Help Center および File Exchange で Classical Control Design についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!