Loop to populate a 12 by 12 matrix

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DARLINGTON ETAJE
DARLINGTON ETAJE 2021 年 6 月 24 日
コメント済み: DARLINGTON ETAJE 2021 年 6 月 24 日
Hello Guys,
I am tryling to form a 12 by 12 matrix for 11 elements. I am getting some errors. Take a look at my code below: it looks perfect to me but it is not working
SC1=rand(11,1);% Test Data
SC2=rand(11,1);
SC3=rand(11,1);
SC4=rand(11,1);
SC5=rand(11,1);
SC6=rand(11,1);
SC7=rand(11,1);
SC8=rand(11,1);
n=size(SC8,1);
K1=zeros(12,1);
K2=zeros(12,1);
K3=zeros(12,1);
K4=zeros(12,1);
K5=zeros(12,1);
K6=zeros(12,1);
K7=zeros(12,1);
K8=zeros(12,1);
K9=zeros(12,1);
K10=zeros(12,1);
K11=zeros(12,1);
K12=zeros(12,1);
K=zeros(12,12);
for i=1:n
K1(i)=[SC1(i);0;0;0;0;0;-SC1(i);0;0;0;0;0];
K2(i)=[0;SC6(i);0;0;0;SC2(i);0;-SC6(i);0;0;0;SC2(i)];
K3(i)=[0;0;SC7(i);0;-SC3(i);0;0;0;-SC7(i);0;-SC3(i);0];
K4(i)=[0;0;0;SC4(i);0;0;0;0;0;-SC4(i);0;0];
K5(i)=[0;0;-SC3(i);0;(2*SC5(i));0;0;0;SC3(i);0;SC5(i);0];
K6(i)=[0;SC2(i);0;0;0;(2*SC8(i));0;-SC2(i);0;0;0;SC8(i)];
K7(i)=-K1;
K8(i)=-K2;
K9(i)=-K3;
K10(i)=-K4;
K11(i)=[0;0;-SC3(i);0;SC5(i);0;0;0;SC3(i);0;(2*SC5(i));0];
K12(i)=[0;SC2(i);0;0;0;SC8(i);0;SC2(i);0;0;0;(2*SC8(i))];
K(i)=[K1(i) K2(i) K3(i) K4(i) K5(i) K6(i) K7(i) K8(i) K9(i) K10(i) K11(i) K12(i)];
end
  1 件のコメント
DARLINGTON ETAJE
DARLINGTON ETAJE 2021 年 6 月 24 日
Thank you so much Walter. It worked. You are an excellent person. The only challenge is that working with the code in struct is different than in a double.

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採用された回答

Walter Roberson
Walter Roberson 2021 年 6 月 24 日
SC1=rand(11,1);% Test Data
SC2=rand(11,1);
SC3=rand(11,1);
SC4=rand(11,1);
SC5=rand(11,1);
SC6=rand(11,1);
SC7=rand(11,1);
SC8=rand(11,1);
n=size(SC8,1);
K1 = repmat({zeros(12,1)},n,1);
K2 = repmat({zeros(12,1)},n,1);
K3 = repmat({zeros(12,1)},n,1);
K4 = repmat({zeros(12,1)},n,1);
K5 = repmat({zeros(12,1)},n,1);
K6 = repmat({zeros(12,1)},n,1);
K7 = repmat({zeros(12,1)},n,1);
K8 = repmat({zeros(12,1)},n,1);
K9 = repmat({zeros(12,1)},n,1);
K10 = repmat({zeros(12,1)},n,1);
K11 = repmat({zeros(12,1)},n,1);
K12 = repmat({zeros(12,1)},n,1);
K = repmat({zeros(12,1)},n,1);
for i=1:n
K1{i} = [SC1(i);0;0;0;0;0;-SC1(i);0;0;0;0;0];
K2{i} = [0;SC6(i);0;0;0;SC2(i);0;-SC6(i);0;0;0;SC2(i)];
K3{i} = [0;0;SC7(i);0;-SC3(i);0;0;0;-SC7(i);0;-SC3(i);0];
K4{i} = [0;0;0;SC4(i);0;0;0;0;0;-SC4(i);0;0];
K5{i} = [0;0;-SC3(i);0;(2*SC5(i));0;0;0;SC3(i);0;SC5(i);0];
K6{i} = [0;SC2(i);0;0;0;(2*SC8(i));0;-SC2(i);0;0;0;SC8(i)];
K7{i} = -K1{i};
K8{i} = -K2{i};
K9{i} = -K3{i};
K10{i} = -K4{i};
K11{i} = [0;0;-SC3(i);0;SC5(i);0;0;0;SC3(i);0;(2*SC5(i));0];
K12{i} = [0;SC2(i);0;0;0;SC8(i);0;SC2(i);0;0;0;(2*SC8(i))];
K{i} = [K1(i); K2(i); K3(i); K4(i); K5(i); K6(i); K7(i); K8(i); K9(i); K10(i); K11(i); K12(i)];
end
K
K = 11×1 cell array
{12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell} {12×1 cell}
K{1}
ans = 12×1 cell array
{12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double} {12×1 double}
K{1}{1}
ans = 12×1
0.3563 0 0 0 0 0 -0.3563 0 0 0

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