When trying smooting the leading edge of airfoil, nothing is changing. Leading edge looks like a arrow. not a circle.
How can ı smoot the leading edge of airfoil.?
x=[0.0 0.5 0.75 1.250 2.5 5.0 7.5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100]./100;
y=[0.0 0.394 0.475 0.594 0.795 1.090 1.322 1.518 1.828 2.066 2.245 2.375 2.459 2.498 2.487 2.420 2.290 2.106 1.881 1.623 1.339 1.038 0.729 0.430 0.165 0.0]./100;
erase=numel(x);
pp=spline(x,y);
xx=sort([x max(x)-0.005 max(x)-0.0075 max(x)-0.0125 max(x)-0.025 max(x)-0.075])
yy=ppval(pp,xx);
x=xx;y=yy;
x=[flip(x) x]; x(numel(xx))=[];
y=[flip(y) -(y)]; y(numel(xx))=[];
plot(x,y)
axis equal

5 件のコメント

onur karakurt
onur karakurt 2021 年 6 月 23 日
its looks like smoothed, please zoom into leading edge.
if thought leading edge so small. please thicken the airfoil then check the leading edge by using
axis equal
DGM
DGM 2021 年 6 月 23 日
I noticed. Since you're doing this problem in halves, it's going to be critical that the endslopes of the halves are vertical.
onur karakurt
onur karakurt 2021 年 6 月 23 日
it must be circle at the leading edge. But I couldnt smoothen at that point of airfoil. Problem is occuring when it is halve, yes, but when unite the lower and upper surface line, it will again happen this problems.
onur karakurt
onur karakurt 2021 年 6 月 23 日
I opened cftool program. is there any function for curvefitting toll with fourier8 , without openning tool page
DGM
DGM 2021 年 6 月 23 日
I'm not that familiar with the depths of the CFT, and I'm not really sure how one would use cftool for this case.

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DGM
DGM 2021 年 6 月 23 日
編集済み: DGM 2021 年 6 月 23 日

0 投票

You could try doing something like this instead of trying to enforce endslopes
x = [0.0 0.5 0.75 1.250 2.5 5.0 7.5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 80 85 90 95 100]./100;
y = [0.0 0.394 0.475 0.594 0.795 1.090 1.322 1.518 1.828 2.066 2.245 2.375 2.459 2.498 2.487 2.420 2.290 2.106 1.881 1.623 1.339 1.038 0.729 0.430 0.165 0.0]./100;
% build a single curve
x = [fliplr(x(2:end-1)) x(2:end-1)];
y = [fliplr(y(2:end-1)) -y(2:end-1)];
% for sake of doing this in polar, x needs to be offset temporarily
% for sake of getting spline to interpolate well, temporarily adjust aspect ratio
xos = 0.5;
ysc = 40;
x = x-xos;
y = y*ysc;
% convert to polar coordinates
r = sqrt(x.^2 + y.^2);
th = atan2(y,x);
th(th<0) = 2*pi+th(th<0);
% do the interpolation
thf = linspace(0,2*pi,1000);
rf = spline(th,r,thf);
% convert back, reposition/rescale, plot
xf = [1 rf.*cos(thf)+xos 1];
yf = [0 rf.*sin(thf) 0]/ysc;
plot(xf,yf); axis equal

2 件のコメント

onur karakurt
onur karakurt 2021 年 7 月 9 日
Thanks so much
onur karakurt
onur karakurt 2021 年 7 月 11 日
please check the trailing edge

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