- Initialize a matrix 'M' which is 1x40 with all zeros, a variable 'remaining_to_place' with 10 which is the count of ones still to be placed in the matrix, a variable 'nmax' to 5 or any other desired value, a variable 'position' to 1 which will contain the location where we have to place a one and a variable 'count' to 0 which will keep track of how many adjacent ones are placed.
- Start a 'while' loop with the condition that 'remaining_to_place > 0'.
- In the body of the while loop place a 'if' check whether 'count < nmax'. If true then increment count by 1, place a one in the matrix at location pointed by position i.e 'M(position)=1', increment position by 1 and decrement 'remaining_to_place' by 1.
- If the result of 'if' was false then in the else part increment 'position' by 1 to break placing more than 'nmax' ones together, set 'count' back to 0.
clustering the random numbers
4 ビュー (過去 30 日間)
古いコメントを表示
Hi, Im having 10 number of ones and 30 zeros places in the random position in 1x40 matrix. now i need to cluster 1's side by side (adjacent 1's) among 10 1's.The max number of adjacent ones is nmax? So if nmax is 5, then maximum number of adjacent ones will be 5.Thank You
0 件のコメント
回答 (1 件)
Arjun
2025 年 2 月 4 日
According to my interpretation of the question, I understand that you have a 1x40 matrix and an argument 'nmax'. The input matrix is such that it contains 10 ones and remaining 30 zeros and the requirement is such that you want to place ones adjacent to one another but no more than 'nmax' number of ones can be adjacent.
Since the total count of ones and zeros is fixed, you can write your algorithm as follows:
Kindly refer to the code below for the implementaion of the above algorithm:
function M = createMatrix(nmax)
% Initialize the matrix and variables
M = zeros(1, 40);
remaining_to_place = 10;
position = 1;
count = 0;
% Place ones in the matrix
while remaining_to_place > 0
if count < nmax
count = count + 1;
M(position) = 1;
position = position + 1;
remaining_to_place = remaining_to_place - 1;
else
position = position + 1;
count = 0;
end
end
end
nmax = 5; % It must be greater than 0
resultMatrix = createMatrix(nmax);
disp(resultMatrix);
Kindly refer to the documenation of 'while' loop here: https://www.mathworks.com/help/releases/R2021a/matlab/ref/while.html
I hope this helps!
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Get Started with MATLAB についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!