num = 0;
L= randperm(10);
for k = L
while L(k)<4
num = num + 1;
L(k) = L(k)+1;
end
end
num = 6 is the answer
Can someone explain why it is 6? Not 3, 4 , or 5?

 採用された回答

James Tursa
James Tursa 2021 年 6 月 14 日

0 投票

Of the numbers 1 ... 10 that get produced by the randperm( ) call, only three of them are less than 4: 1, 2, 3.
1 will cause num to increase three times
2 will cause num to increase two times
3 will cause num to increase one time
three + two + one = 6

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2021 年 6 月 14 日

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