finding only unique values

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Bernard
Bernard 2013 年 8 月 22 日
Suppose you have a column vector, the values are integers(in order) but some of them are repeated, e.g. it could be [1,1,1,1,2,3,3,4,5,5,5,5,5] I want to find the indices of unique values e.g. the index of 2 and 4 in the aforementioned example. the unique function in matlab returns on top of truly unique the first value of any nonunique value, so it would return the index of the first 1, the first 3 and first 5 but I don't want those

採用された回答

the cyclist
the cyclist 2013 年 8 月 22 日
編集済み: the cyclist 2013 年 8 月 22 日
Maybe call these the "singleton" values. Here's one way:
x = [1,1,1,1,2,3,3,4,5,5,5,5,5];
unique_x = unique(x);
count_x = hist(x,unique_x);
singleton_x = unique_x(count_x==1)
  1 件のコメント
Bernard
Bernard 2013 年 8 月 22 日
brilliant this saved me time thanks

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その他の回答 (2 件)

David Sanchez
David Sanchez 2013 年 8 月 22 日
a=[1,1,1,1,2,3,3,4,5,5,5,5,5];
x = unique(a)
y = histc(a,x)==1;
lonely_values = find ( y == 1 )
or:
lonely_values = find ( (histc(a,unique(a))==1) == 1 )
lonely_values =
2 4

Azzi Abdelmalek
Azzi Abdelmalek 2013 年 8 月 22 日
[ii,jj]=sort(x);
out=sort(jj(strfind(logical([1 diff(ii) 1]),[true,true])))

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