finding only unique values
3 ビュー (過去 30 日間)
古いコメントを表示
Suppose you have a column vector, the values are integers(in order) but some of them are repeated, e.g. it could be [1,1,1,1,2,3,3,4,5,5,5,5,5] I want to find the indices of unique values e.g. the index of 2 and 4 in the aforementioned example. the unique function in matlab returns on top of truly unique the first value of any nonunique value, so it would return the index of the first 1, the first 3 and first 5 but I don't want those
0 件のコメント
採用された回答
the cyclist
2013 年 8 月 22 日
編集済み: the cyclist
2013 年 8 月 22 日
Maybe call these the "singleton" values. Here's one way:
x = [1,1,1,1,2,3,3,4,5,5,5,5,5];
unique_x = unique(x);
count_x = hist(x,unique_x);
singleton_x = unique_x(count_x==1)
その他の回答 (2 件)
David Sanchez
2013 年 8 月 22 日
a=[1,1,1,1,2,3,3,4,5,5,5,5,5];
x = unique(a)
y = histc(a,x)==1;
lonely_values = find ( y == 1 )
or:
lonely_values = find ( (histc(a,unique(a))==1) == 1 )
lonely_values =
2 4
0 件のコメント
Azzi Abdelmalek
2013 年 8 月 22 日
[ii,jj]=sort(x);
out=sort(jj(strfind(logical([1 diff(ii) 1]),[true,true])))
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Get Started with MATLAB についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!