Handling odd-sized integers
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I have a horrible binary file format, which does have a defined format, and which can contain several odd types of data.
I have loaded the entire file to memory as uint8 data, as the code needs to work on remotely-networked servers, and this is faster than repeated disk accesses.
I have 4 bit, 3 bit, 2 bit and 1 bit integer data fields which may be signed. A single byte can contain two or more fields.
e.g. Field 1: 2 bits, Field 2: 2 bits, Field 3: 4 bits
Currently, for each field, I read the entire byte, right shift it (bitsra) to make the relevant bits the LSB's, use bitand to eliminate the upper, unused bits. If the field is signed, I check the uppermost bit in my valid area, and then set all higher bits equal to the same value using bitor, then I typecast it into int8.
I have a similar process using 2 and 4 bytes for the 24 bit and 12 bit integer fields.
Are there any faster bit operation functions than bitand/bitor/bitsra?
3 件のコメント
Walter Roberson
2013 年 8 月 21 日
If you are doing large numbers of these in the same way, then using vectorized arithmetic operations would probably be faster than the bit* operations.
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