How to find the 12th highest value for every year

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Nicky Benedict
Nicky Benedict 2021 年 6 月 7 日
回答済み: Nicky Benedict 2021 年 6 月 9 日
I have a data set that I have made into a table and used the sort funtion to make it into descending order based on the year followed by the 2nd column values i.e.
2014 3.98 10.34
2014 3.93 10.24
2014 3.90 10.18
.
.
.
2006 0.61 5.05
2006 0.54 5.01
2006 0.52 4.98
2006 0.50 4.89
2006 0.50 4.79
I want to find the 12th highest value for each year (the 12th row for every year).
The number of data measurements for each year are not equal. For example, in year 2014 there might be 12000 rows but in year 2010 there may only be 11500 rows of data
Thank you in advance.

採用された回答

Nicky Benedict
Nicky Benedict 2021 年 6 月 9 日
I figured it out.
T_sort = sortrows(T,[1,2,3],'descend');
[yr,index] = unique(T_sort.Years);
index_new = index + 11;
hour_12 = T_sort(index_new,:);

その他の回答 (1 件)

SALAH ALRABEEI
SALAH ALRABEEI 2021 年 6 月 7 日
Since you already sorted them, what you need to do now is call the first highest 12 as follows
% Assuming the matrix is A where the 1st col is the years.
B = [];
years = unique(A(:,1));
for i = 1: length(years)
B= [B,(A(A(:,1)==years(i),12))];
end
  3 件のコメント
Nicky Benedict
Nicky Benedict 2021 年 6 月 9 日
The approach you took ended up just giving me the years but I managed to figure it out with the help of the "unique" function you had in your code. Thank you for all your help. I appreciate it. I posted my code down below if you want to know what I did.

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