# Plotting a circular region from a function

18 ビュー (過去 30 日間)
Chuck Noise 2021 年 6 月 4 日
コメント済み: Chuck Noise 2021 年 6 月 15 日
I am working on a analysis of different numerical methods and I am trying to plot the stability region of a numerical method.
For instance if we look at the absolute stability requirements for the explicit euler method we get the condition
which yields the region of absolute stability in the complex plain shown in the image below
where
Now for this exact method the stability is a perfect circle and I could find a way to simply plot a circle with a radius of 1 and a center in (0,-1), but for most cases it isnt a perfect circle but rather a skewed one.
I tried making the circle through a function handle with the variable z where I plotted it from -2<=z<=0 but it didnt turn out as I hoped.
Is there anyone that can help me in forming an function, or something else, from the inequality and similiar inequalities?
Thanks

サインインしてコメントする。

### 採用された回答

Vimal Rathod 2021 年 6 月 7 日
Below is a link to a similar question which might be of help to you.
##### 1 件のコメント表示 なし非表示 なし
Chuck Noise 2021 年 6 月 15 日
Thanks a lot :)

サインインしてコメントする。

### カテゴリ

Help Center および File Exchange2-D and 3-D Plots についてさらに検索

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by