フィルターのクリア

In Quiver Function Error: " index must be a positive integer or logical."

2 ビュー (過去 30 日間)
Daniel
Daniel 2013 年 8 月 13 日
Hey,
I get the error
??? Attempted to access quiver(2.76604,2.17365,-0.123257,0.81116); index must be a positive integer or logical.
and can't imagine why, because if I type quiver(2.76604,2.17365,-0.123257,0.81116) in the Command Window it works well.
Here is the Code:
for k=1:n
for l=1:n
if E(k,l) >= 1
x1=2+cos(2*pi/n*k); x2=2+cos(2*pi/n*l); y1=2+sin(2*pi/n*k); y2=2+sin(2*pi/n*l);
u=y1-x1; v=y2-x2;
quiver(x1,x2,u,v);%,'Color',color,'LineWidth',2);
end
end
end
with n=length(E) and E(i,j) = 1 if there excists an arrow between i and j
Thank You Daniel
  3 件のコメント
Daniel
Daniel 2013 年 8 月 13 日
Hmm this is weird because if I run exactly your modification of the code I get the error:
??? Attempted to access quiver(1.5,1.5,1.36603,1.36603); index must be a positive integer or logical.
Error in paintgraph at 23
quiver(x1,x2,u,v);
I can't imagine why. Yes the code I presented yields the error.
Daniel
Daniel 2013 年 8 月 13 日
Got the solution. I accidantly set quiver=1 earlier.
Thank you very much.

サインインしてコメントする。

採用された回答

Sajid Khan
Sajid Khan 2013 年 8 月 13 日
use clear all before executing your code.

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeNaming Conventions についてさらに検索

タグ

製品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by