Fourier Transform of a random Signal

17 ビュー (過去 30 日間)
Kutlu Yigitturk
Kutlu Yigitturk 2021 年 6 月 1 日
回答済み: Sulaymon Eshkabilov 2021 年 6 月 1 日
t = 0 : 0.001 : 2;
x = (2*(exp(-4*t))).*(cos(10*t).*unit(t))
subplot(2,1,1)
plot(t,x)
grid
I wrote such a code for this signal, but I don't know how to get the fourier transform of this signal. Thank you very much in advance for your help.

採用された回答

Sulaymon Eshkabilov
Sulaymon Eshkabilov 2021 年 6 月 1 日
Hi,
Here is the complete code:
t = 0 : 0.001 : 2;
x = (2*(exp(-4*t))).*(cos(10*t).*heaviside(t));
L= numel(x);
Y = fft(x);
M2 = abs(Y/L);
M1 = M2(1:L/2+1);
M1(2:end-1) = 2*M1(2:end-1);
dt=.001;
Fs = 1/dt;
f = Fs*(0:(L/2))/L;
subplot(2,1,1)
plot(t,x)
grid on
subplot(212)
plot(f, abs(M1))
xlim([0, 50]), grid on
xlabel('f, [Hz]')
ylabel('|X|')

その他の回答 (0 件)

カテゴリ

Help Center および File ExchangeDiscrete Fourier and Cosine Transforms についてさらに検索

製品


リリース

R2021a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by