A question about the freqz function
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Hi,
My name is Robert and I´m having a minor problem with the freqz function in MATLAB. I´m using it to get the frequency response from a filter in the following way:
H=freqz(zeros,poles,frequency vector,sampling frequency)
however, when I plot the phase in the following way:
plot(180/pi*angle(H))
I don´t get the same phase characteristics as i get if i just write
freqz(zeros,poles,512,sampling frequency)
how do I get the same phase characteristics?
Thanks in advance Sincerely Robert
2 件のコメント
Walter Roberson
2011 年 5 月 29 日
I am not familiar with that function, but I wonder if perhaps you should unwrap() the angle(H) ?
回答 (1 件)
Paulo Silva
2011 年 5 月 29 日
Try this way:
[h,w]=freqz(zeros,poles,frequency vector,sampling frequency)
plot(frequency vector,w)
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