the "taylor" function does not work for me (beginner)

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Szczepan Michura
Szczepan Michura 2021 年 5 月 25 日
コメント済み: the cyclist 2021 年 5 月 26 日
typing expressions under "taylor()" i get the message that "Unrecognized function or variable 'Taylor'"
should I download this program function from somewhere?
syms x
T1 = taylor (exp (x));
T2 = taylor (sin (x));
T3 = Taylor (cos (x));

回答 (1 件)

the cyclist
the cyclist 2021 年 5 月 26 日
In the assignment statement for T3, you capitalized "Taylor". MATLAB is case-sensitive, so you must use "taylor".
  4 件のコメント
Szczepan Michura
Szczepan Michura 2021 年 5 月 26 日
is this normal?
the cyclist
the cyclist 2021 年 5 月 26 日
Yes, it is normal to get "not found" if you misspell the name of the command.
Maybe you meant ...
help taylor
--- help for sym/taylor --- TAYLOR(f) is the fifth order Taylor polynomial approximation of f about the point x=0 (also known as fifth order Maclaurin polynomial), where x is obtained via symvar(f,1). TAYLOR(f,x) is the fifth order Taylor polynomial approximation of f with respect to x about x=0. x can be a vector. In case x is a vector, multivariate expansion about x(1)=0, x(2)=0,... is used. TAYLOR(f,x,a) is the fifth order Taylor polynomial approximation of f with respect to x about the point a. x and a can be vectors. If x is a vector and a is scalar, then a is expanded into a vector of the same size as x with all components equal to a. If x and a both are vectors, then they must have same length. In case x and a are vectors, multivariate expansion about x(1)=a(1),x(2)=a(2),... is used. In addition to that, the calls TAYLOR(f,'PARAM1',val1,'PARAM2',val2,...) TAYLOR(f,x,'PARAM1',val1,'PARAM2',val2,...) TAYLOR(f,x,a,'PARAM1',val1,'PARAM2',val2,...) can be used to specify one or more of the following parameter name/value pairs: Parameter Value 'ExpansionPoint' Compute the Taylor polynomial approximation about the point a. a can be a vector. If x is a vector, then a has to be of the same length as x. If a is scalar and x is a vector, a is expanded into a vector of the same length as x with all components equal to a. Note that if x is not given as in taylor(f,'ExpansionPoint',a), then a must be scalar (since x is determined via symvar(f,1)). It is always possible to specify the expansion point as third argument without explicitly using a parameter value pair. 'Order' Compute the Taylor polynomial approximation with order n-1, where n has to be a positive integer. The default value n=6 is used. 'OrderMode' Compute the Taylor polynomial approximation using relative or absolute order. 'Absolute' order is the truncation order of the computed series. 'Relative' order n means the exponents of x in the computed series range from some leading order v to the highest exponent v + n - 1 (i.e., the exponent of x in the Big-Oh term is v + n). In this case, n essentially is the "number of x powers" in the computed series if the series involves all integer powers of x Examples: syms x y z; taylor(exp(-x)) returns x^4/24 - x^5/120 - x^3/6 + x^2/2 - x + 1 taylor(sin(x),x,pi/2,'Order',6) returns (pi/2 - x)^4/24 - (pi/2 - x)^2/2 + 1 taylor(sin(x)*cos(y)*exp(x),[x y z],[0 0 0],'Order',4) returns x - (x*y^2)/2 + x^2 + x^3/3 taylor(exp(-x),x,'OrderMode','Relative','Order',8) returns - x^7/5040 + x^6/720 - x^5/120 + x^4/24 - x^3/6 + ... x^2/2 - x + 1 taylor(log(x),x,'ExpansionPoint',1,'Order',4) returns x - 1 - 1/2*(x - 1)^2 + 1/3*(x - 1)^3 taylor([exp(x),cos(y)],[x,y],'ExpansionPoint',[1 1],'Order',4) returns exp(1) + exp(1)*(x - 1) + (exp(1)*(x - 1)^2)/2 + ... (exp(1)*(x - 1)^3)/6'), cos(1) + (sin(1)*(y - 1)^3)/6 - ... sin(1)*(y - 1) - (cos(1)*(y - 1)^2)/2 taylor(exp(z)/(x - y),[x,y,z],'ExpansionPoint',[Inf,0,0], ... 'OrderMode','Absolute','Order',6) returns y^2/x^3 + z^2/(2*x) + z^3/(6*x) + z^4/(24*x) + y/x^2 + ... z/x + 1/x + (y*z)/x^2 + (y*z^2)/(2*x^2) See also SYM/SYMVAR, SYM/SYMSUM, SYM/DIFF, SUBS. Documentation for sym/taylor doc sym/taylor

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