MATLAB Answers

How can I separate the data into two groups.?

5 ビュー (過去 30 日間)
zhoug zho
zhoug zho 2021 年 5 月 21 日
回答済み: Kartikay Sapra 2021 年 5 月 21 日
How can I separate the data into two groups.
  1. If the first element of a column is largest number of that column, such type of columns are placed into one group.
  2. If the largest number is not at the first position of that column and is present as 2nd 3rd 4thor any other position of that column, then such columns are placed in one group.
I need to form two groups of this data. Screenshot of data is attached. I highlighted few coloumn's largest number.
Thanks in advance.
  3 件のコメント
Daniel Bengtson
Daniel Bengtson 2021 年 5 月 21 日
So you basically need to compare the first element in each column against the maximum value in each column. If they are equal then that column goes in the first group, otherwise the column would go in the second group.

サインインしてコメントする。

採用された回答

David Fletcher
David Fletcher 2021 年 5 月 21 日
編集済み: David Fletcher 2021 年 5 月 21 日
%Get index of max values in each column
[val idx]=max(data)
%Create logical vector of max values where the max value is the first in the
%column
gp1_idx=(idx==1)
%Use logical vector to index out columns for one group
group1=data(:,gp1_idx)
%Use (not)logical vector to index out columns of the other group
group2=data(:,~gp1_idx)
  2 件のコメント
David Fletcher
David Fletcher 2021 年 5 月 21 日
If you are ignoring zeros why have you got 0 marked as the max in the first column? Not sure I get it.

サインインしてコメントする。

その他の回答 (1 件)

Kartikay Sapra
Kartikay Sapra 2021 年 5 月 21 日
data = [-1 -2 -1; 0 -1 0; 0 0 0]
data(data==0) = NaN
[maxVal ids] = max(data)
data(isnan(data))=0
part_a = data(1:end,ids==1)
part_b = data(1:end,~(ids==1))
When finding the maximum, just keep the indices of non-zero values by making zeros 'NaN'. After that, NaN values dont interfere with max/min so after retrieving the indices, change NaN back to 0.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by