How to change seconds since 1st January 1985 to YYYY-MM-DD-HR-M-S format?
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I am a new user of MATLAB and was hoping to get some help to what is probably a very basic question to most of you. I am using data that currently represents time in seconds since 1st January 1985 and have been trying to change this to a format of YYYY-MM-DD-HR-M-S, however my attempts have been completely unsuccessful thus far. The data I am using ranges from 2003-2008. This is as much as I have come up with so far.
> t=86400; %86400 seconds in a day
> datestr(t/86400+datenum(1985,1,1))
Any help or guidance would be really appreciated. Cheers
1 件のコメント
Jan
2013 年 7 月 29 日
What do you get as result of your code and what do you expect? I'd suggest exactly the same way, because it is the most efficient one.
回答 (2 件)
Azzi Abdelmalek
2013 年 7 月 29 日
編集済み: Azzi Abdelmalek
2013 年 7 月 29 日
dat0='01-01-1985 00:00:00'
dat00=datevec(dat0,'dd-mm-yyyy HH:MM:SS')
a=95604
dat00(6)=dat00(6)+a
new_de=datestr(datenum(dat00))
1 件のコメント
Jan
2013 年 7 月 29 日
Your dat00 contains the same information as David's datenum(1985,1,1). Adding the number of seconds to the 6.th component of the date vector is the same as adding t/86400 to the datenumber. Therefore I do not see the difference to the original approach.
Iain
2013 年 7 月 29 日
seconds_since_1985 = 981364894; %
days_since_1985 = seconds_since_1985 / 86400;
datestr(days_since_1985 + datenum('1/1/1985'), 'YYYY-MM-DD-hh-mm-ss')
1 件のコメント
Jan
2013 年 7 月 29 日
This looks also identical to the original version.
"MM" means minutes, while "mm" means months. So you have to swap upper- and lower-case.
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