Interp2 a set of randomly sampled points?

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MikeStein
MikeStein 2013 年 7 月 25 日
Hello All,
I am given the following information with no guarantee on any particular order or sample spacing (there could be holes. Roughly on a hexagonal grid, but not precicely...)
- Vectors of X and Y locations corresponding to a same-sized vector of complex values which I want to interpolate.
I've written the following test case which works great:
% Simple test case first to test handling of phasors:
test = [0 2*pi 0.1;
-0.1 0 -2*pi;
0 0 0;]
test = exp(1i*test);
[testX, testY] = meshgrid(1:3)
interpX = [1.5; 2.5; 2.1];
interpY = [1.5; 1.5; 2];
testInterp = interp2(testX,testY,test, interpX, interpY);
angle(testInterp)
% It works!
Unfortunately, I don't get my data in these nicely formatted and arranged square matricies. I get them in vectors, which don't have any particular order. I modified the above code to mimic this, and get errors complaining that the vectors are no longer monotonically increasing... I've tried sorting the data by x or y, but I keep getting the errors. Since the x coords are coupled with the y coords, I can't sort both x and y at the same time (does that make sense?). Any way, maybe the code below helps:
test = [0 2*pi 0.1;
-0.1 0 -2*pi;
0 0 0;]
test = exp(1i*test);
[testX, testY] = meshgrid(1:3)
interpX = [1.5; 2.5; 2.1];
interpY = [1.5; 1.5; 2];
combinedVector = [testX(:), testY(:), test(:)];
combinedVector = sortrows(combinedVector, [2 1]);
testInterp = interp2(combinedVector(:,1),combinedVector(:,2),combinedVector(:,3), interpX, interpY);
angle(testInterp)
Thoughts?? -Mike
  1 件のコメント
dpb
dpb 2013 年 7 月 25 日
look at
doc triscatteredinterp

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採用された回答

MikeStein
MikeStein 2013 年 7 月 25 日
Interesting function! I modified my script (below) to accept this, but it doesn't give the results I expect. They are close, but don't match the first test script I wrote (and is correct). Thoughts?
% Simple test case first to test handling of phasors:
test = [0 2*pi 0.1;
-0.1 0 -2*pi;
0 0 0;]
test = exp(1i*test);
testR = real(test);
testI = imag(test);
[testX, testY] = meshgrid(1:3)
interpX = [1.5; 2.5; 2.1];
interpY = [1.5; 1.5; 2];
Fr = scatteredInterpolant(testX(:), testY(:), testR(:))
Fi = scatteredInterpolant(testX(:), testY(:), testI(:))
angle(Fr(interpX, interpY) + 1i*Fi(interpX, interpY))
Thanks!
  3 件のコメント
dpb
dpb 2013 年 7 月 25 日
Jim has it basically between interp2 and triscattered
I don't know about the FEX submission but you can also look at
*griddata"
There's a decent background section in the doc's on interpolating scattered data that outlines at least the basics of the methods implemented
MikeStein
MikeStein 2013 年 7 月 29 日
Thanks All!! That was the guidance I needed!! -Mike

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