Several tangent vectors on curve

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Viktor Karlsson
Viktor Karlsson 2021 年 5 月 14 日
コメント済み: Viktor Karlsson 2021 年 5 月 17 日
Hello,
I have the following curve plotted:
Now, I want 10 tangent vectors along this curve and I can't seem to figure out how to write the code for this to work. I wrote the following:
t = linspace(-2.5,2.5,100);
x = t.^3 - 4*t;
y = t.^2;
plot(x,y,'LineWidth',2)
axis equal
hold on
i=1:10:100;
ts=t(i);
xs=x(i);
ys=y(i);
tx = ts.^3 -4*ts;
ty = ts.^2;
quiver(tx,ty,xs,ys,'LineWidth',2,'Color','r')
hold off
and the result is.. not quite it:
Any help or advice is appreciated.

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the cyclist
the cyclist 2021 年 5 月 14 日
編集済み: the cyclist 2021 年 5 月 14 日
Well, you never actually calculated the tangent, so it is not that surprising you didn't get the correct result.
t = linspace(-2.5,2.5,100);
x = t.^3 - 4*t;
y = t.^2;
dydt = 2*t;
dxdt = 3*t.^2 - 4;
dydx = dydt./dxdt;
i=1:10:100;
ts=t(i);
xs=ones(size(i));
ys=dydx(i);
tx = ts.^3 -4*ts;
ty = ts.^2;
figure
hold on
plot(x,y,'LineWidth',2)
quiver(tx,ty,xs,ys,'LineWidth',2,'Color','r')
axis equal
Apologies for rearranging your code to my liking. See this page for the math of calculating the tangent of a parametric equation. (You'll need to be careful if dx/dt is ever zero, because you divide by that.)
Also, I was lazy and just set the length of the x-component of the tangent vector to (positive) 1, then calculated the y-component. You probably want something less lazy.
  3 件のコメント
the cyclist
the cyclist 2021 年 5 月 14 日
As I mentioned, I always defined the x-component of the tangent vector as +1; therefore, it will always be toward the right.
The parametric equation has no inherent "direction", and the tangent line extends in both directions from any given point.
Viktor Karlsson
Viktor Karlsson 2021 年 5 月 17 日
I understand, thank you helping!

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