fill a matrix with binary code in a for loop

Hi,

in a for-loop I get 30 times 3 bits each. To display the bits in a vector is no problem for me. But I would like to have a matrix after the 30 passes. Unfortunately my approach does not succeed.

for i = 1:30
% I reveive:
bit1 = [0] 
bit2 = [1]
bit3 = [1]

% create Vektor works fine:
bitcode = [bit1 bit2 bit3]

% create Matrix doesnt work:
bitcode(i, :) = [bit1 bit2 bit3]
% neither that way:
for k = 1:length(bitcode)
    bitcode(i,k) = bit(k)
end
end

Result should look like:

bitcode = [0 1 1; 1 1 1; 1 0 1]

I guess I'm doing something wrong?

[David Fletcher]

I'm not sure how you expect to get a 3 row matrix when you are using a row indexing loop that iterates 30 times to create the matrix, nor am I sure how you expect each row to be different when it is based on the same arrangement of bits. However as a general example of using a loop to create a matrix, this might be of help:

code = [0 1 1]

for k = 1:length(bitcode)
    bitcode(k,:) = code
end

[Christian]

thank you! you are absolutely right. logic is sometimes not very strong with me. your solution works, thank you very much!:)

(@David Fletcher: I would like to confirm your statement as an answer, unfortunately I can't do that since you used the comment function)

[David Fletcher]

Ok, I'll post it as an answer if it helped you, but it's not a big deal to me

Answer 1

[David Fletcher]

code = [0 1 1]
for k = 1:length(bitcode)
    bitcode(k,:) = code
end