# Need half of my contour plot

7 ビュー (過去 30 日間)
Maryam 2013 年 7 月 18 日
Hello I have a contour of the pressures over a surface. Basically, I had vectors x and y which were locations on the surface and on each location, I had a value for pressure. I have a rectangular plot. I was wondering if there is a way to split my plot from the diagonal and show just the results for either upper or lower triangles?

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### 採用された回答

Kye Taylor 2013 年 7 月 18 日

Check out the tril and triu functions. For example if you have data similar to
[x,y]= meshgrid(-1:.05:1);
z = x.^2+y.^2;
contour(x,y,z)
Try something like
zLowerTri = tril(z);
contour(x,y,zLowerTri)
Since contour plots with the origin at lower left instead of upper right, you may prefer either
zLowerTri = tril(z);
contour(x,y,zLowerTri)
axis ij
or
contour(x,y,fliplr(tril(fliplr(z))))
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Maryam 2013 年 7 月 19 日
Thank you very much. I now have what I wanted.

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### その他の回答 (1 件)

Pourya Alinezhad 2013 年 7 月 18 日

hello maryam, run following lines of code.
x=0:0.1:10;
y=x;
j=1;
z=meshgrid(x,y);
h=ones(length(x),length(x))*nan;
for i=1:length(x)
for j=1:length(y)
if i>j
h(i,j)=z(i,j);
end
end
end
surf(sin(h)./sqrt(h))
figure
contourf(sin(h)./sqrt(h))

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