Help indexing: How to index at the interfaces of cells and not the cells

1 回表示 (過去 30 日間)
Jamie Al
Jamie Al 2021 年 5 月 7 日
編集済み: per isakson 2021 年 5 月 9 日
I am struggling to understand how to setup some indexing problem in MATLAB. If my entire domain is defined from 1 to N with a padding of two cells. So say my internal domain (domain without padded cells) from 2 to N-2, then if I want to calculate some values at the "interfaces" of the cells instead at the cells, how can I setup this on MATLAB? For example I have the following code for the internal domain that I would like to change my indicies to the interfaces?
My set up is like:
% calculate Flux at j+1/2
%
% j+1/2 Cell's grid:
% | wL| |
% | /|wR | 1 2 3 4 N-2 N-1 N
% | / |\ | {x=0} |-o-|-o-|-o-|-o-| ... |-o-|-o-|-o-| {x=L}
% |/ | \ | 1 2 3 4 5 N-1 N N+1
% | | \|
% | | | NC: Here cells 1 and N are ghost cells%
% j j+1
I keep getting the error:
Index in position 2 exceeds array bounds
The code for example:
function [ U_L, U_R] = MUSCL(U,N,NEQ )
size_U = size(U);
U_L = zeros(size_U);
U_R = zeros(size_U);
delta = 1e-6; % epsilon
for i= 1:NEQ
for j = 3:N-1
denom_L = (U(i,j) - U(i,j-1));
denom_R = (U(i,j+2) - U(i,j+1)); % error here since index exceeds the bounds of the array N (1001 here)
denom_L = sign(denom_L+1e-64)*max(delta, abs(denom_L));
denom_R = sign(denom_R+1e-64)*max(delta, abs(denom_R));
r_L = (U(i,j) - U(i,j-1))/denom_L;
r_R = (U(i,j+2) - U(i,j+1))/denom_R;
theta_L = Limiter(r_L);
theta_R = Limiter(r_R);
end
end
for j = 2:N-2
U_L(:,j) = U(:,j)+0.5*theta_R.*(U(:,j)-U(:, j-1));
U_R(:,j) = U(:,j+1)-0.5*theta_L.*(U(:,j+2)-U(:,j+1));
end
end
How can I find U_L, U_R, r_L, r_R at j+1/2 ??

採用された回答

per isakson
per isakson 2021 年 5 月 8 日
編集済み: per isakson 2021 年 5 月 8 日
Index in position 2 exceeds array bounds
U(:,j+2) is most likely the problem.
I assume that the size of U is NEQxN. The maximum value of j is N-1 (for j = 3:N-1). Thus, the maximum value of j+2 is N+1, which exceeds the array bound, N
  2 件のコメント
Jamie Al
Jamie Al 2021 年 5 月 8 日
Yes so I changed j to go from 2:N-2 and the code works but I am still getting wrong results for UL and UR which suggest maybe I am not really caclulating those two at the interfaces of the cells
per isakson
per isakson 2021 年 5 月 9 日
編集済み: per isakson 2021 年 5 月 9 日
Your code is about "flux", "cells" and "interfaces". The name, MUSCL, does that stand for "muscle"? However, I neither understand the physics nor the code. Futhermore, I cannot run the code, since I neither have the function, Limiter(), nor a realistic sample of U.
It looks strange to me that none of the left-hand-side variables in the double loop is indexed.
I've made a little demo in response to your answer to @DGM.
%% A sample matrix
M = 40 .* membrane( 1, 25 );
%%
to_the_interfaces = @(row) interp1( (1:numel(row)), row, (1.5:1:numel(row)-0.5) );
row = (1:10);
to_the_interfaces(row)
ans = 1×9
1.5000 2.5000 3.5000 4.5000 5.5000 6.5000 7.5000 8.5000 9.5000
%%
M_at_the_interfaces = nan(size(M)-[0,1]);
for jj = 1 : size(M,1)
M_at_the_interfaces(jj,:) = to_the_interfaces(M(jj,:));
end
imagesc( M_at_the_interfaces )

サインインしてコメントする。

その他の回答 (1 件)

DGM
DGM 2021 年 5 月 8 日
編集済み: DGM 2021 年 5 月 8 日
Just interpolate.
x = 0:10;
y = x.^2
xhalf = 0.5:9.5;
yhalf = interp1(x,y,xhalf,'linear')
plot(x,y,'rd',xhalf,yhalf,'bo')
  1 件のコメント
Jamie Al
Jamie Al 2021 年 5 月 8 日
I have no clue how to apply this in my example. Can you show something for my for loop?

サインインしてコメントする。

カテゴリ

Help Center および File ExchangeMatrix Indexing についてさらに検索

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by