Drawing upside down cone using spherical coordinates.

I wrote the following code:
phi=pi/6;
theta=linspace(0,2*pi,63); %Theta goes from 0 to 2*pi.
a=linspace(0,1,21);
[PHI,THETA,A]=meshgrid(phi,theta,a);
X=A.*sin(PHI).*cos(THETA); % Spherical coordinates
Y=A.*sin(PHI).*sin(THETA);
Z=A.*cos(PHI);
surf(X,Y,Z)
axis equal
It won't draw, but instead gives me an empty 2D graph.
The error message is:
Error using matlab.graphics.chart.primitive.Surface
Value must be a vector or 2D array of numeric type.
Error in surf (line 145)
hh = matlab.graphics.chart.primitive.Surface(allargs{:});

 採用された回答

Benjamin Kraus
Benjamin Kraus 2021 年 4 月 30 日

1 投票

The issue you are facing is that when you call meshgrid you are specifying three input vectors, so the output matrices are going to be 3D matrices, but surf only accepts 2D matrices.
My recommendation is to remove phi from the call to meshgrid:
phi=pi/6;
theta=linspace(0,2*pi,63);
a=linspace(0,1,21);
[THETA,A]=meshgrid(theta,a);
X=A.*sin(phi).*cos(THETA);
Y=A.*sin(phi).*sin(THETA);
Z=A.*cos(phi);
surf(X,Y,Z)
axis equal

1 件のコメント

Viktor Karlsson
Viktor Karlsson 2021 年 5 月 3 日
Thank you so much for taking the time to help, works like a charm!

サインインしてコメントする。

その他の回答 (0 件)

カテゴリ

ヘルプ センター および File ExchangeDates and Time についてさらに検索

製品

リリース

R2020a

タグ

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by