Questions about bvp4c solution
古いコメントを表示
Hi, I solved correctly a system of ODE second order with BCs, with the instruction bvp4c.
However, I have some questions about it.
My code is as follows:
...
xmesh = linspace(1e-5,1.5*1e-3,20);
solinit = bvpinit(xmesh,1e-3*[0,0,0,0,1,1,1,1]);
sol = bvp4c(@bvpfcn,@bcs,solinit);
plot(sol.x,sol.y)
1) When I plot the solution, I should choose in x interval sol.x or xmesh? What is their difference?
2) I don't understand how Matlab uses the second vector [0,0,0,0,1,1,1,1] in bvpinit.
It should represent the initial guess of solution (I have 8 variables), but it seems that its values don't change final solution. Is it right?
I've already read Matlab guide about bvp4c, but I have not found these answers.
Thank you!
採用された回答
その他の回答 (0 件)
カテゴリ
ヘルプ センター および File Exchange で Boundary Value Problems についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!