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Creating a 2-D matrix from a 1-D Array?

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Sabarinathan Vadivelu
Sabarinathan Vadivelu 2013 年 7 月 5 日
Considering that I have an array of A = [150 11 12 134 130 152]. How to replicate these elements in this array to get a matrix of size 256*256.

採用された回答

Matthew Eicholtz
Matthew Eicholtz 2013 年 7 月 5 日
Based on your comment to David's answer, how about this?
r = 256; % number of desired rows
c = 256; % number of desired columns
Avec = repmat(A(:),ceil(r*c/length(A)),1); % vector of repeated A values
Anew = reshape(Avec(1:r*c),c,r)'; % new 2-D matrix of size rxc

その他の回答 (2 件)

David Sanchez
David Sanchez 2013 年 7 月 5 日
You do not make clear how you want to replicate your data, but this is a way:
A = [150 11 12 134 130 152];
L = numel(A); % number of elelments in A
M = zeros(256); % initialize the matrix
% assigin values to first row
for k = 0:floor(256/L)
M( 1 , (k*L+1):((k+1)*L) ) = A;
end
% make sure you only have your 256 columns
M = M(:,1:256);
% copy first row to the rest of rows
for k=2:256
M(k,:) = M(1,:);
end
  1 件のコメント
Sabarinathan Vadivelu
Sabarinathan Vadivelu 2013 年 7 月 5 日
The overflowed elements in the previous rows should start from the next row.
for example,
150 11 12 134 130 152 150 11 12
134 130 150 11 12 134 130 152 11
12 . . . . . . .
. . . . . .
. . . . . .

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Andrei Bobrov
Andrei Bobrov 2013 年 7 月 5 日
編集済み: Andrei Bobrov 2013 年 7 月 5 日
out = A(randi(numel(A),256,256));
or
m = 256;
n = 256;
A1 = repmat(A,1,ceil((m+n-1)/numel(A)));
out = hankel(A1(1:m),A1(m:m+n));

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