repeating the loop until condition is met

Hello,

I have a prog, in which I have to repeat the function until a condition is met.

I used while loop, but it is running only once and coming out of the loop.

My code looks somewhat like this. It is a lengthy prog, hence just posting the gist.

iteration=0

while 1

calling a function which will give me an array

the returned array is checked to meet a specific requirement

if the requirement is not met, then call the function again.

iteration=iteration+1;

end

[DGM]

I know what you wrote is just pseudocode, but it doesn't contain any exit condition. As given, it would be an infinite loop, which is contrary to what you describe. I'd need to know how you intend for the loop to exit.

If your while loop doesn't have an exit condition described in the first line (e.g. like this:)

% specify the exit condition normally
error=1;
while error>tol
	% do stuff
	error=abs(thing1-thing2);
end

Then it will have to break conditionally like this:

% or break out directly
while 1
	% do stuff
	if thinghappens
		break;
	end
end

Without knowing what the exit condition is and how it's satisfied, there's no way to answer this question with greater specificity. If it's exiting early, observe the value of the variables used to satisfy the exit condition and try to see if they are achieving their required values early or if the logical tests are incorrectly evaluating them.

[NETHRAVATHI S]

Thank you.

I got the solution. I did like this.

while 1
	% do stuff
	if thinghappens
		break;
	end
end

[per isakson]

More standard

thinghappens = false;
while  not( thinghappens ) 
    % do stuff
end

[DGM]

I can agree to that, but I was hoping that the obvious hint would be that the two can be combined.

while ~normalexitcondition
    % do stuff
    if abnormalexitcondition
        warning('oh no!')
        break;
    end
end