How to open file array with fopen?

Question

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Hi, I have a list of files that look like this:

J={'File1', 'File2', 'File3'}

It is not possible to open the file using fopen this way:

 for i=1:length(J)
   fid=fopen('J(1)', 'r')
   %Some algorithms here...
   fclose(fid)
 end

Is there any possible way to use fopen by using looping? It seems like it only accepts the actual file name. Please help. Thanks!

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Answer 1

Jonathan Sullivan 2013 年 7 月 1 日

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You just need to index into J properly. J looks to be a cell array so you need to use curly brackets.

Try replacing your fopen line with this

fid = fopen(J{i},'r');

Jacky 2013 年 7 月 1 日

It works. I thought I did that and it it didn't work. It must be something that I missed earlier on. Thank you so much for pointing that out for me.

Answer 2

Walter Roberson 2013 年 7 月 1 日

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