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Horizontal First Differencer on a Matrix

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Sarah Maas
Sarah Maas 2021 年 4 月 18 日
コメント済み: Sarah Maas 2021 年 4 月 18 日
I have a matrix M and I need to implement a first differencer along the horizontal dimension as follows such that the value of each element is replaced by:
y[n, m] = x[n, m] x[n, m 1]
Where n and m be the independent variables (integer indices) indexing the matrix elements along the vertical and horizontal dimensions, respectively.

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Bjorn Gustavsson
Bjorn Gustavsson 2021 年 4 月 18 日
Have a look on the help and documentation to diff. For this case use:
y = diff(x,[],2);
% or explicitly 1st difference:
y = diff(x,1,2);
% or manually:
y = x(:,2:end) - y(:,1:end-1);
HTH
  1 件のコメント
Sarah Maas
Sarah Maas 2021 年 4 月 18 日
Thank you. Can you also tell me how i can derive the frequency response of the above?

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