Implicit plane curve discretization
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I want to have a matrix with 2 lines and n columns with the coordinates of points that lie on the implicit curve where is a function. I know that the matlab function fimplicit can plot the curve. So in its subroutines it grabs a set of points from\near that curve. How can I extract those points and use them for future calculations (like the perimeter of the curve)?
Thanks!
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Matt J
2021 年 4 月 16 日
編集済み: Matt J
2021 年 4 月 16 日
fp=fimplicit(@(x,y) x.^2 + 2*y.^2 - 1); %Example
Points=[fp.XData;fp.YData]
3 件のコメント
Walter Roberson
2021 年 4 月 17 日
fp = fimplicit(@(x,y) x.^2 + 2*y.^2 - 1, 'visible', 'off'); %Example
Points = [fp.XData;fp.YData]
delete(fp)
However this creates a graphic object -- so for example if you have no existing figure then one will be created with an axes in it (that just will not have any visible content.)
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