Rotating a Cylinder to fit the line x=y=z
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[sig_1, sig_2, sig_3] = cylinder;
%sig_3 = sig_3 * 2;
g = surf(sig_1,sig_2,sig_3);
direction =[1 1 1];
rotate(g,direction, 45)
xlabel("x");
ylabel("y");
zlabel("z");
title('Von Mises Yield Surface')
hold on
Q = plot3([0 2], [0 2], [0 2]);
hold off
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/575162/image.png)
Any help or refrence to a source that might help will be greatly appreciated
1 件のコメント
採用された回答
DGM
2021 年 4 月 7 日
The vector you're using is the vector you're trying to align the cylinder to. The vector you need to be specifying is the axis of rotation, which should be orthogonal to [1 1 1]. It also seems that rotate() likes to move the origin around depending on the plot box, so you'll have to make it stop doing that by explicitly specifying a coordinate origin. Lastly, the rotation angle isn't 45 degrees.
clf
[sig_1, sig_2, sig_3] = cylinder;
g = surf(sig_1,sig_2,sig_3);
rotaxis = [135 0]; % i decided to do this polar instead of cart
rotate(g,rotaxis,90-atand(1/sqrt(2)),[0 0 0])
xlabel('x');
ylabel('y');
zlabel('z');
title('Von Mises Yield Surface')
hold on
axis equal
Q = plot3([0 2], [0 2], [0 2]);
Q = plot3([1 -1], [-1 1], [0 0]);
hold off
And like I said, the angle isn't 45. It's easy enough to derive, though.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/575212/image.jpeg)
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