Plotting the graph of change in Work wrt Crank Angle Degree
3 ビュー (過去 30 日間)
古いコメントを表示
I am trying to plot the graph of Work with respect to Crank Angle Degrees. I have tried the code in following way.
% The pressure data
pressure=xlsread('C:\Users\HP\Desktop\PROJECT WORK\Data.csv','M2:M1242');
Q=pressure*100;
% The Volume data
volume=xlsread('C:\Users\HP\Desktop\PROJECT WORK\Data1.csv','C2:C1242');
Z=volume*10^-9;
P0=101.325;
x=-160:0.25:150;
n=numel(x);
V= zeros(n,1);
w= zeros(n,1);
A= zeros(n,1);
for i= 1:numel(x)
v=Z(i);
V(i)=((0.249)*(10^-3))*sind(x(i)).*(1+((0.28*cosd(x(i)))./(sqrt(1-(0.0784*(sind(x(i)))^2)))));
P=Q(i);
w(i)=(P-P0).*V(i);
A(i)=trapz(i, w);
end
plot(x,A','r')
X axis values are in Crank Angle Degrees
Y axis values are in Kilo Joules (kJ)
Kindly Suggest me the following things:
1.) If the code that I have written is correct.
2.) If the syntax for trapezoidal rule for Integration is right.
3.) How to check where the errors in getting the exact plot lies
2 件のコメント
回答 (1 件)
darova
2021 年 4 月 2 日
What about limits? Here are limits for
. But what about limits for
?
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/570674/image.png)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/570679/image.png)
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/570684/image.jpeg)
I think this line should be changed
%A(i)=trapz(i, w);
A(i) = trapz(x(1:i),w(1:i));
Read about cumtrapz
0 件のコメント
参考
カテゴリ
Help Center および File Exchange で Surface and Mesh Plots についてさらに検索
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!