System Failure and Monte Carlo Simulation

How do i calculate the probaility of system failure if the probability of failure of 4 independent components are as follows, A=0.01, B=0.04, C=0.06, D=0.03. Also, how would i relate this to monte carlo simulation

[William Rose]

Does the system fail if any 1 or more fails, or do they all hav to fail at once for the system to fail?

If system fails when all fail at once, then you multiply the probabilities (since they are independent).

If failure of any one or more causes system failure then you "OR" them:

Pfail=1-Pnonefail=1-(1-A)*(1-B)*(1-C)*(1-D)

[logan jackson]

Thank you for the answer, yes its if one or more cause failure. Would i need to consider if multiple components fail at once?

[William Rose]

See the ealrier comment about not-a-homeowrk-servce. And my 2nd answer did tak that into account.

Answer 1

[Shubham Khatri]

Hello,

Given that the probabilities of failure are A=0.01, B=0.04, C=0.06, D=0.03. We calculate the probability that none of the components would fail and subract that probability with 1. This gives us the probability where atleast one component fails (including the possibility that more than one componant fails).

To know more about ,how to use the Monte-Carlo Simulation, please refer to this file exchange link to guide you with the code.

Hope it helps