compare 2 matrix with different dimensions
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Hi, assume that I have a matrix 'info' (800,3), the first column is for ID, the second column is for coordinate x and the last column is for coordinate y. Additionally I have a matrix called 'coordinates'(200,2) where the first column is coordinate x and the second is coordinate y. I want to compare this matrix with the 'info' matrix to find the IDs where the matrix 'coordinates' is equal to the 'info' matrix.
Thanks
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Walter Roberson
2013 年 6 月 10 日
[tf, idx] = ismember( info(:,2:3), coordinates, 'rows');
match_IDs = info(tf, 1);
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Azzi Abdelmalek
2013 年 6 月 10 日
編集済み: Azzi Abdelmalek
2013 年 6 月 10 日
A=[1 10 20;2 100 200;3 1000 2000;4 44 55]
B=[11 20;100 200;1 4;44 55 ]
out=A(~any(A(:,2:3)-B,2),1)
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Walter Roberson
2013 年 6 月 11 日
any() by default works along the first dimension (so down columns), but it accepts an optional dimension number. dimension #2 means across rows.
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