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How Define Delta Function

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Kutlu Yigitturk
Kutlu Yigitturk 2021 年 3 月 24 日
コメント済み: Kutlu Yigitturk 2021 年 3 月 24 日
I have a problem about calculating with Delta Function. I am trying write matlab code for these function.
I wrote the following code for this function.
n = -5:1:7;
x = delta(n+1) - delta(n) + unit(n+1) - unit(n-2);
stem(n,x,'fill');
axis([-6 8 -1.5 1.5])
xlabel('n')
ylabel('x[n]')
grid
But I am getting the following error.
I don't now how can ı write the delta function in this way ,
function y = unit(x);
y = zeros(size(x));
y(x>0) = 1;
end
Can you help me write the delta function as the 'unit' function you see above? Thank you for your helping.

採用された回答

Star Strider
Star Strider 2021 年 3 月 24 日
If you have the Symbolic Math Toolbox, use the dirac function. It can be used with non-symbolic arguments as well.
  4 件のコメント
Walter Roberson
Walter Roberson 2021 年 3 月 24 日
That is not a true Dirac δ function.
delta = @(x) x==0;
unit = @(x) x>=0;
n = -5:1:7;
x = delta(n+1) - delta(n) + unit(n+1) - unit(n-2);
stem(n,x,'fill');
axis([-6 8 -1.5 2])
xlabel('n')
ylabel('x[n]')
grid
Kutlu Yigitturk
Kutlu Yigitturk 2021 年 3 月 24 日
Thank you for your help Mr. Roberson. I got the result I wanted.

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