write this code in matlab

step 1 read the image

 then write it in a 2-d array(matrix) 
assign i=1 and j=1 (1=rows, j= columns) 
assign A(i,j)=X (this is array)
 A(i,j-1)=A 
A(i-1,j)=B 
now give context=AB (which should be 00,01,10,11 any one of them)
 if { 
context=00
 { 
if 
X=0 
{   c0(00)=1+c0(00) }
 else if X=1 
{ c1(00)=1+c1(00) (at start c1(00) c0(00) all are equal to zero) } 
cont(00)=1+cont(00)
}
 else if context=01
 { if x= 0 
{ 
c0(01)=1+c0(01)
 } 
else if X=1 
{
 c1(01)=1+c1(01) 
} 
cont(01)=1+cont(01)
 } 
else if context=10 
{
if X=0 
{ 
c0(10)=1+c0(10)
 } else if X=1 
{
  c1(10)=1+c1(10) 
} 
cont(10)=1+cont(10) 
} 
else if context=11
 {
 if X=0 { c0(11)=1+c0(11) 
}
 else if X=1 
{ 
c1(11)=1+c(11) 
}
 cont(11)=1+cont(11)
 } 
if j<256 (size of the image is 256*256 then we should take 256)
 {
j=j+1
 } 
else if j=256 
{ i=i+1
} if i=256 && j=256 (both should 256)
 end 
else go to
 {
 assign A(i,j)=X (it should go back to this) 
} then i have to find out some float values when displaying this it should c0me steady state probabilities p(00)=cont(00)/(total number of counts i think it will be the size of the matrix 256*256) 
p(01)=cont(01)/(256*256)
 p(10)=count(10)/(256*256)
 p(11)=count(11)/(256*256) }
 now display these all the below conditional probabilities p0(00)=c0(00)/cont(00) 
p1(00)=c1(00)/cont(00) 
p0(01)=c0(01)/cont(01) 
p1(01)=c1(01)/cont(01) 
p0(10)=c0(10)/cont(10) 
p1(10)=c1(10)/cont(10) 
p0(11)=c0(11)/cont(11) 
p1(11)=c1(11)/cont(11) 
similarly all the values then h(00)=p0(00)logbase2(1/p0(00)) +p1(00)logebase2(1/(p1(00)

h(01)=p0(01)logbase2(1/p0(01)) +p1(01)logebase2(1/(p1(01)

so onll ti h(11) can we write h(00)= h(AB)?? these 00,01,10,11 are actually AB it is very hard how to write all and display all these assign h(s) entropy= p(AB)H(AB) end the way i wrote in my notes p(00)h(00)+p(01)h(01)+p(10)h(10)+p(11)h(11) display all these values }

[Walter Roberson]

http://www.mathworks.com/matlabcentral/answers/13205-tutorial-how-to-format-your-question-with-markup

Please reformat; your question is difficult to read.

[Jan]

Do you have a specific question or do you assume that we solve the complete problem for you?

[faraz.a]

i know you will not solve i just have questions in between the code i mentioned in comments. new in matlab dont know anything about it so trying to solve step by step

Answer 1

[Image Analyst]

Indexes have to be integers like 1, 2, 3, etc. (or logical true/false) - you can't have an index of 00. You'll have to figure that out. And, MATLAB code doesn't use { to start a block, and it uses "end" instead of } to finish a block. Comments begin with a % symbol. I, for one, don't have time to fix your code or translate it into MATLAB code for you. Good luck.

[faraz.a]

thank you

[faraz.a]

how to read the image and write it in a 2-d array matrix?

[faraz.a]

can i write

 if A=0 && B=0

 c0(00)=1+c0(00)
  end ??

[Walter Roberson]

You can write

if A==0 && B==0

but you cannot write

c0(00)

because you cannot index anything at 0.

You can define

 i00 = 1;
 i01 = 2;
 i10 = 3;
 i11 = 4;

and then use i00 everywhere you used 00, use i01 everywhere you used 01, and so on.

[faraz.a]

okay

d=imread("coin.tif")
size(d)
fid = fopen('coin.tif','rb');       opens the file
M = fread(fid, [rows columns], 'int16')
M = reshape(M,[r c]);
disp(M)
i00=1
i01=2
i10=3
i11=4
c0(i00)=0,c1(i00)=0,c0(i01)=0,c1(i01)=0,c0(i10)=0,c1(i10)=0,c0(i11)=0,c1(i11)=0   %can i define it this way?
i=1 and j=1 % i=rows, j= columns 

 for i from 1 to 256 do %(i hope it increments every time)
for j from 1 to 256 do
M(i,j)=X 
M(i,j-1)=A 
M(i-1,j)=B 
 if A==0 && B==0
  if X=0 
  c0(i00)=1+c0(i00)
  end   % do i need to write end over here?
 else if X=1 
c1(i00)=1+c1(i00) 
end
cont(i00)=1+cont(i00)
end
 else if A==0 && B==1
  if x= 0 
 c0(i01)=1+c0(i01)
end
else if X=1 
 c1(i01)=1+c1(i01) 
end
cont(i01)=1+cont(i01)
end
else if A==1 && B==0 
if X=0  
c0(i10)=1+c0(i10)
 end
else if X=1 
  c1(i10)=1+c1(i10) 
end
cont(i10)=1+cont(i10) 
end
else if A==1 && B==1
 if X=0 
c0(i11)=1+c0(i11) 
end
 else if X=1 
c1(i11)=1+c(i11) 
end
 cont(i11)=1+cont(i11)
end
cont=1+cont
end_for
end_for 

 c0me steady state probabilities 
p(i00)= mod(cont(i00),cont) 
p(i01)= mod(cont(i01),cont)
p(i10)= mod(cont(i10),cont)
p(i11)= mod(cont(i11),cont)
 now display these all the below conditional probabilities p0(i00)=mod(c0(i00),cont(i00))
p1(i00)= mod(c1(i00),cont(i00))
p0(i01)= mod(c0(i01),cont(i01))
p1(i01)= mod(c1(i01),cont(i01)) 
p0(i10)= mod(c0(i10),cont(i10)) 
p1(i10)= mod(c1(i10),cont(i10))
p0(i11)= mod(c0(i11),cont(i11)) 
p1(i11)= mod(c1(i11),cont(i11)) 
h(i00)= -p0(i00)log2(p0(i00))- p1(i00)log2(p1(i00))
h = p(i00)*h(i00)+p(i01)*h(i01)+p(i10)*h(i10)+p(i11)*h(i11)
end
now will this display all the values or i need to write something to display?
is this the way i need to write in matlab?

[faraz.a]

i will execute and ask if i get errors thank you so much for your guidance sir