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Convert xy Coordinates to Matrix

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John
John 2013 年 5 月 26 日
コメント済み: Image Analyst 2021 年 3 月 24 日
I have an xy coordinates positions (100x2) and another z vector (100x1) with values corresponding to each xy coordinate. How can I make a matrix of the coordinates with the position of each coordinate having the corresponding z value? Thanks!

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Andrei Bobrov
Andrei Bobrov 2013 年 5 月 27 日
編集済み: Andrei Bobrov 2013 年 5 月 27 日
after John's comment in Image Analyst's answer:
out = accumarray([x(:),y(:)],z(:),[10 10]);
or
out = zeros(10);
out(sub2ind(size(out),x,y)) = z;
  4 件のコメント
John
John 2013 年 5 月 27 日
Now I get it, thanks for the clarification.
cecilia dip
cecilia dip 2016 年 11 月 28 日
Hi, I have to do the same thing, and i've tried this, but my coordinates (x,y) are negative and non-integer numbers, as they are latitude,longitude.. how can i do this? I want a plot where for each(lat,long) i can have my Z value (in a color scale, as i will compare it with interpolation methos later). Thank you!

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その他の回答 (2 件)

Image Analyst
Image Analyst 2013 年 5 月 26 日
Try this:
% Setup / initialization.
% Start out matrix as zeros.
m = zeros(20,10);
% Generate 100 random coordinates.
xy = int32(randi(10, 100, 2));
% Get matrix values for those x,y locations
z = randi(255, 100, 1); % 100 values.
% Now, do what the poster, John, wants to do.
% Assign the z values to the (x,y) coordinates at the corresponding row.
% E.g. m at (x(1), y(1)) will have a value of z(1).
% m at (x(2), y(2)) will have a value of z(2). And so on.
indexes = sub2ind([20, 10], xy(:,1), xy(:,2))
m(indexes) = z
  6 件のコメント
Luigi Izzo
Luigi Izzo 2021 年 3 月 24 日
what about if xy(k,1) or xy(k,1) are negative numbers?
Thanks
Image Analyst
Image Analyst 2021 年 3 月 24 日
Try using a scatteredInterpolant. Demo attached.
If you still need help, attach your x, y, and z data in a new question (not here) so people can help you.

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Annisa Dewanti Putri
Annisa Dewanti Putri 2018 年 7 月 10 日
thanks for the help

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