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Problem with the product of complex numbers

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clement
clement 2013 年 5 月 24 日
Hello,
I calculated the equivalent impedance of an RLC circuit, and I would like this one to be completely resistive (complex part equals to 0). So I declared my variables as 'syms' and I used the function 'solve' to obtain the equivalent impedance litterally like:
% syms R X Y Z
% Zeq=solve('(R+i*X)*(-i*Y)/(R+i*X-i*Y)=Z',Z)
The problem is that Matlab gives me a solution like this:
%Zeq =
% -(Y*(R + X*i)*i)/(R + X*i - Y*i)
But I would like something like: Zeq = A + i*B.
Could anyone help?
Thanks

採用された回答

Jonathan Epperl
Jonathan Epperl 2013 年 5 月 24 日
Probably simplify(Zeq) will do that.
  2 件のコメント
Walter Roberson
Walter Roberson 2013 年 5 月 24 日
expandsol = expand(sol);
A = real(expandsol);
B = imag(expandsol);

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その他の回答 (1 件)

Walter Roberson
Walter Roberson 2013 年 5 月 24 日
You cannot do that unless you add the assumption that the variables are real-valued
syms R X Y Z real
Zeq = simplify(solve((R+i*X)*(-i*Y)/(R+i*X-i*Y)-(Z),Z));
A = simplify(real(Zeq));
B = simplify(imag(Zeq));
A + B*i
  8 件のコメント
Jonathan Epperl
Jonathan Epperl 2013 年 5 月 25 日
I see, I didn't know that -- so A-50 is the more robust syntax...

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