Reduce Matrix size with interpolated data arrays
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Hi,
I have a 360*720 precipitation matrix with values in milimeter, and i desire a 180*360 matrix with interpolated data to compare my precipitation with other 180*360 data.
here you can see the original 360*720 plot of my data. please help me on this.
Thank you.
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採用された回答
Mathieu NOE
2021 年 3 月 10 日
hello
simply use a 2D interpolation with the appropriate new Xq and Yq vectors
interp2 2-D interpolation (table lookup).
Vq = interp2(X,Y,V,Xq,Yq) interpolates to find Vq, the values of the
underlying 2-D function V at the query points in matrices Xq and Yq.
Matrices X and Y specify the points at which the data V is given.
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その他の回答 (1 件)
Jan
2021 年 3 月 11 日
The mean over neighboring rows and columns is smarter than a linear interpolation, which just omits the intermediate rows and columns:
x = rand(360, 720);
y = x(1:2:end, :) + x(2:2:end, :);
z = (y(:, 1:2:end) + y(:, 2:2:end)) / 4;
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