MATLAB Answers

Locating point on x-axis where the slope is decreasing

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Tessa Kol
Tessa Kol 2021 年 3 月 10 日
コメント済み: Star Strider 2021 年 3 月 10 日
Dear all,
I used the following code to plot the angle over time:
figure
hold on
grid on
plot(Time, theta,'linewidth',1.5)
xlabel('Time [s]','FontWeight','bold')
ylabel('\theta [deg]','FontWeight','bold')
xlim([0 round(Time(end))])
legend('Opening angle','Location','northeast')
title('Opening angle')
The resulting graph is shown below. I want to index at what time the slope is decreasing. How can I do that?
The variables Time and theta to plot this graph can be found in the data.mat file.

採用された回答

Star Strider
Star Strider 2021 年 3 月 10 日
A reasonably robust way is to use the ischange function:
D = load('data.mat');
Time = D.Time;
theta = D.theta;
[TF,m,b] = ischange(theta, 'linear', 'Threshold',5);
chgpts = [find(TF); m(TF); b(TF)].';
chgidx = find(chgpts(:,2)<0,1);
figure
plot(Time, theta,'linewidth',1.5)
hold on
plot(Time(chgpts(chgidx(:,1))), theta(chgpts(chgidx(:,1))), 'xr')
hold off
grid on
xlabel('Time [s]','FontWeight','bold')
ylabel('\theta [deg]','FontWeight','bold')
xlim([0 round(Time(end))])
legend('Opening angle','Location','northeast')
title('Opening angle')
producing:
The ‘Time’ value is then:
ChangePointTime = Time(chgpts(chgidx(:,1)));
that here is 6.01 seconds.
  4 件のコメント
Star Strider
Star Strider 2021 年 3 月 10 日
As always, my pleasure!

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その他の回答 (1 件)

Sargondjani
Sargondjani 2021 年 3 月 10 日
Bascially you want to get the index when the change in theta becomes negative:
dtheta = diff(theta);
index = find(dtheta<0,1);%the 1 refers to the first entry where the statement is true

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